100 Watt inverter circuit
Description
Here is a 100 Watt inverter circuit using minimum number of components.I think it is quite difficult to make a decent one like this with further less components.Here we use CD 4047 IC from Texas Instruments for generating the 100 Hz pulses and four 2N3055 transistors for driving the load.
The IC1 Cd4047 wired as an astable multivibrator produces two 180 degree out of phase 100 Hz pulse trains.These pulse trains are preamplifed by the two TIP122 transistors.The out puts of the TIP 122 transistors are amplified by four 2N 3055 transistors (two transistors for each half cycle) to drive the inverter transformer.The 220V AC will be available at the secondary of the transformer.Nothing complex just the elementary inverter principle and the circuit works great for small loads like a few bulbs or fans.If you need just a low cost inverter in the region of 100 W,then this is the best.
Circuit Diagram with Parts List.
Notes.
- A 12 V car battery can be used as the 12V source.
- Use the POT R1 to set the output frequency to50Hz.
- For the transformer get a 9-0-9 V , 10A step down transformer.But here the 9-0-9 V winding will be the primary and 220V winding will be the secondary.
- If you could not get a 10A rated transformer , don’t worry a 5A one will be just enough. But the allowed out put power will be reduced to 60W.
- Use a 10 A fuse in series with the battery as shown in circuit.
- Mount the IC on an IC holder.
- Remember,this circuit is nothing when compared to advanced PWM inverters.This is a low cost circuit meant for low scale applications.
Design Tips.
The maximum allowed output power of an inverter depends on two factors.The maximum current rating of the transformer primary and the current rating of the driving transistors.
For example ,to get a 100 Watt output using 12 V car battery the primary current will be ~8A ,(100/12) because P=VxI.So the primary of transformer must be rated above 8A.
Also here ,each final driver transistors must be rated above 4A. Here two will be conducting parallel in each half cycle, so I=8/2 = 4A .
These are only rough calculations and enough for this circuit.
design of electronic circuits is my field of study (bsc. physics)
Hi Hamisu Ahmed kindly send your your fine designs to Circuits today. we will all be benifitted.
thanks. awaiting your designs
what to do with the remaining pins 12,13,14 of the IC 4047?
how to check the operation of each component when i connect a 12 v Dc supply?..
how to know whether the POT R1 is adjusted at 50Hz?
please reply:-(
Hi Pin 14 should be connected to plus 12 volt supply. 12 & 13 not to be used as we donot require those functions. If you have a multimeter you can check the out put voltage connect a 60Watt bulb and try whether the glow is not flickering. if you have a frequency meter check for the frequency at the out put. if you do not have any test gear connect a bulb if it is glowing alright, connect a 230V 50Hz table fan to the inverter output and slowly turn the frequency pot till the fan speed gets peaked(runs almost at the same speed like when it is connected to mains supply). in this crude method you can adjust the freq. approximately.
thanx a lot:-))
Can any one give me the pcb layout of 100watt inverter..Its an urgent…Plz
Can the watt of this inverter be increased? Can I use powerful transistor to increase wattage? What kind of wave output of this circuit (sine or square)?
Thanks 4 publ such a ckt. Every electronic professionalist gets lots m
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Hai,how to check the battery ah,
i have connect the two 6v battery whether, the 12v battery
Hi Sat the ampere hour capacity is given on the battery by the manuacturer. If you use 6 volt 7 ah two numbers in series, then 12 volt 7ah will be the capacity of the battery.
Will it be very harmful if I use 120W load?
Can I increase wattage by adding another 2N3055 parallel to these two. If so is there any other changes required (for Q1, Q2, R2, R3)?
Hi Imteaz A small change to be carried out in the circuit for proper operation. Shift +12 volt to fuse. include 470 ohms between fuse and supply of IC 4047 (between fuse and zener with 220uF capacitor). Add 4700uF 25volt capacitor in parallel with 0.1uF capacitor between centre tap of out put transformer and supply negative, nearer to 2N3055 emitter resistance(in other words in parallel with D1 BY127). You can connect 2 more 2N3055 also Q1 and Q2 can take care. IC can give a drive of 1mA which is sufficient to drive 4 to 5 2N3055 transistors through TIP122. Do not forget emitter resistance for 2N3055s. Increase fuse rating to 20Amps. Out put transistors wire dressing will be critical and important be careful.
I am thinking of designing an inverter in which its output(AC),is fed back to charge the battery when it undergoes low voltage and vise versa,and this oscillation goes on continuously,ie,automatically.
Can you provide me a full circuit diagram with parts list?
Thank you in advance.
Daniel.
Hi Daniel battery DC to covert to AC there will be a loss of 25% and again convert AC to DC and charge battery another 25% loss. Hence this is not viable proposition. It is something like connecting motor to dynamo mechanically and connecting dynamo and motor electrically thinking that it is perpetual and run for ever if you take all the losses into consideration this is not viable. Say even if it is 100% efficient what are you going to achieve, you cannot tap power from the system due this loss the system will collapse.
Hi, Can you tell me the values Q5 and Q6 and calculate the working hours of 100w equipment with 12volt,7Ah battery? please
Hi! Wil u please tell u know about the function of zener diode n can v replace the ic cause its in astable mood so v can use any in this mood……n y here 2 100hetz in this y not 120hetz… Please give me reply…
Hi Anoop Q5 & Q6 are also 2N3055 like Q3 & Q4. Say inverter efficiency is 80% for 100 watts load you require 125VA input with 12 volt battery you require 14 Amps current. Hence with 7AH battery you will get approximately just less than 30minutes.
Hi Imran You can change the frequency to your requirement with pot R1. Zener to regulate the supply to the IC oscillator so that its frequency output is stable. There is a mistake in the circuit refer to my earlier comments on 2nd May.