40V 2A Power Supply Circuit LM 317
Description.
This is the circuit diagram of of a 40V power supply able to deliver 2A current.This circuit is suitable for power amplifiers .Transistor TIP 42 A is used as a pass transistor to increase the current capabilities.Voltage regulator LM 317 is the heart of this circuit .Here the out put voltage is set to 40 V by R5 & R8.If you want any other out put voltage use a 10 K pot instead of R5 and adjust it.
Parts List.
R1_______________3R9 1 or 2W Resistor
R2______________ 22R 1/4W Resistor
R3_______________6K8 1/4W Resistor
R4_____________ 220R 1/4W Resistor
R5_______________4K7 1/2W Resistor
C1____________ 3300µF 50V Electrolytic Capacitor (or 4700µF 50V)
C2,C5__________ 100nF 63V Polyester Capacitors
C3______________ 10µF 63V Electrolytic Capacitor
C4_____________ 220µF 50V Electrolytic Capacitor
D1_____ Diode bridge 4A
D2___________ 1N4002 Diode
D3______________ LED Any color
U1___________ LM317
Q1____________ TIP42A Transistor
T1_____________ 230V Primary, 40V 2A ,Secondary,
Mains transformer.
Note.
If diode bridge is not available make one using four 1N 4007 Diodes.
Circuit Diagram.Click to Enlarge.
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Here the out put voltage is set to 40 V by R5 & R8.If you want any other out put voltage use a 10 K pot instead of R5 and adjust it.
Dear Admin,
On the above quote, I am confused, I can not find R8, and R5 is a series resistor for LED (D3).
Can you make clarification on this circuit?, I would like to build one for this.
Thanks in advance.
Hi Edgardo,
you are correct. there is a mistake in the writeup.
R5 is the current limitting resistance for the LED.
output can be varied with R3(10K pot).
Dear Seetharaman,
Thank you very much for the information,
More power to you.