Diode Clippers – An overview of Clipping Circuits

Diode Clippers – A study of  various Clipping Circuits

This article explains the working of different diode clipper circuits like Positive and Negative Diode Clippers, Biased Clipper circuit, and Combinational Clipper Circuit with the help of circuit diagrams and waveforms.

The basic components required for a clipping circuit are – an ideal diode and a resistor. In order to fix the clipping level to the desired amount, a dc battery must also be included.  When the diode is forward biased, it acts as a closed switch, and when it is reverse biased, it acts as an open switch. Different levels of clipping can be obtained by varying the amount of voltage of the battery  and also interchanging the positions of the diode and resistor.

Depending on the features of the diode, the positive or negative region of the input signal is “clipped” off and accordingly the diode clippers may be positive or negative clippers.

There are two general categories of clippers: series and parallel (or shunt). The series configuration is defined as one where diode is in series with the load, while the shunt clipper has the diode in a branch parallel to the load.

1. Positive Clipper and Negative Clipper

Positive Diode Clipper

In a positive clipper, the positive half cycles of the input voltage will be removed. The circuit arrangements for a positive clipper are illustrated in the figure given below.

Series and Shunt Clipper Circuits


As shown in the figure, the diode is kept in series with the load. During the positive half cycle of the input waveform, the diode ‘D’ is reverse biased, which maintains the output voltage at 0 Volts. Thus causes the positive half cycle  to be clipped off. Dur­ing the negative half cycle of the input, the diode is forward biased and so the nega­tive half cycle appears across the output.

In Figure (b), the diode is kept in parallel with the load. This is the diagram of a positive shunt clipper circuit. During the positive half cycle, the diode ‘D’ is forward biased and the diode acts as a closed switch. This causes the diode to conduct heavily. This causes the voltage drop across the diode or across the load resistance RL to be zero. Thus output voltage during the positive half cycles is zero, as shown in the output waveform. During the negative half cycles of the input signal voltage, the diode D is reverse biased and behaves as an open switch. Consequently the entire input voltage appears across the diode or across the load resistance RL if R is much smaller than RL

Actually the circuit behaves as a voltage divider with an output voltage of [RL / R+ RL] Vmax = -Vmax when RL >> R

Negative Diode Clipper

The negative clipping circuit is almost same as the positive clipping circuit, with only one difference. If the diode in figures (a) and (b) is reconnected with reversed polarity, the cir­cuits will become for a negative series clipper and negative shunt clipper respec­tively. The negative series and nega­tive shunt clip­pers are shown in figures (a) and (b) as given below.

Negative clipper circuits

In all the above discussions, the diode is considered to be ideal one. In a practical diode, the breakdown voltage will exist (0.7 V for silicon and 0.3 V for Germanium). When this is taken into account, the output wave­forms for positive and negative clippers will be of the shape shown in the figure below.


Clipping circuit waveforms
Negative and Positive Clipping Waveforms


2. Biased Positive Clipper and Biased Negative Clipper

A biased clipper comes in handy when a small portion of positive or negative half cycles of the signal voltage is to be removed. When a small portion of the negative half cycle is to be removed, it is called a biased negative clipper. The circuit diagram and waveform is shown in the figure below.

Biased Negative Clipping Circuit

TIn a biased clipper, when the input signal voltage is positive, the diode ‘D’ is reverse-biased. This causes it to act as an open-switch. Thus the entire positive half cycle appears across the load, as illustrated by output wave­form [figure (a)]. When the input signal volt­age is negative but does not exceed battery the voltage ‘V’, the di­ode ‘D’ remains reverse-biased and most of the input voltage ap­pears across the output. When during the nega­tive half cycle of input signal, the signal voltage becomes more than the battery voltage V, the diode D is forward biased and so conducts heavily. The output voltage is equal to ‘- V’ and stays at ‘- V’ as long as the magnitude of the input signal voltage is greater than the magnitude of the battery voltage, ‘V’. Thus a biased negative clipper removes input voltage when the input signal voltage becomes greater than the battery voltage. Clipping can be changed by reversing the battery and diode connections, as illustrated in figure (b).

Biased Positive Clipping Circuit

Some of other biased clipper circuits are given below in the figure. While drawing the wave-shape of the output basic principle discussed above are followed. The diode has been considered as an ideal one.


Types of Clipping Circuits
Different Clipper Circuits

3. Combination Clipper

When a portion of both positive and negative of each half cycle of the input voltage is to be clipped (or removed), combination clipper is employed. The circuit for such a clipper is given in the figure below.

Combination Clipping Circuit


The action of the circuit is summarized below. For positive input voltage signal when input voltage exceeds battery voltage ‘+ V1 diode D1 conducts heavily while diode ‘D2‘ is reversed biased and so voltage ‘+ V1‘ appears across the output. This output voltage ‘+ V1‘ stays as long as. the input signal voltage exceeds ‘+ V1‘. On the other hand for the negative input voltage signal, the diode ‘D1‘ remains reverse biased and diode ‘D2‘ conducts heavily only when input voltage exceeds battery voltage ‘V2‘ in magnitude. Thus during the negative half cycle the output stays at ‘- V2‘ so long as the input signal voltage is greater than ‘-V2‘.


Drawbacks of Series and Shunt Diode Clippers

  • In series clippers, when the diode is in ‘OFF’ position, there will be no transmission of input signal to output. But in case of high frequency signals transmission occurs through diode capacitance which is undesirable. This is the drawback of using diode as a series element in such clippers.
  • In shunt clippers, when diode is in the ‘off condition, transmission of input signal should take place to output. But in case of high frequency input signals, diode capacitance affects the circuit operation adversely and the signal gets attenuated (that is, it passes through diode capacitance to ground).

To gain more knowledge about various other Clipping circuits – say Clipping circuits using Transistors, Applications of Diode clippers etc. Follow the links below.





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77 thoughts on “Diode Clippers – An overview of Clipping Circuits

  1. Soham Desai

    It was helpful but more emphasis should be given on the working of biased clipper, like how do they actually work and what happens with the help of schematic diagrams… Otherwise a very helpful article



    • athul

      when the diode is forward biased current flow is high… so to protect the diodes from the heavy flow of current , resistors are used in series…

  3. Tittu Thomas

    You are right, the biased negative clipper output wave form doesnt clipped off.

    I think it will clipped on -(V+D)

    v is the voltage source
    D is the drop in diode

  4. iZZa

    I think “Biased Negative Clipper” figure output waveform is wrong. ! let me know if it is my mistake. thanks anyway

  5. Rajish kumar

    please explain combine diode circuit with Rquation solver by 3 steps which are given in Boylested Book….

  6. Yeahia

    if some mathematical problem is included with explanation,it will be so helpful.But this makes me understand the clippers,thanks

  7. Muhammet

    Hi I am a physics department student, i have a question abuot last picture, if we turn the dc voltage supllies 180 degree, then how it would be the Vout signal

  8. vandana joshi

    i want to know that when diode is in series with load and battery then why another level v or -v is introduced in output waveform

  9. gopika

    pls explain more abt clippers. explain shunt & series clippers in 2 versions. thats all THANK U 4 ur help.

  10. physics king

    really wonderful!!!!!!!!!!
    but images are too small………
    combination clipping information is less………
    if diode is not ideal no diagrams are mentioned…..

  11. ramakant

    really nice description… but images r too small..

    @jeena— all the current will pass through the diode when forward bias leaving no voltage drop accros the resistor..too simple to understand…

  12. seetharaman

    Hi you have to sufficiently amplify the signal before feeding to this clipping circuit if input is less than 600mV nothing will happen to the waveform as the diode cannot conduct.
    the output cannot be greater than 600mv (1200mV pk – pk) so you have to amplify further to increase the waveform level.

  13. Jeena

    what about the drop across R when shut clipper is considered. When will you tell the diode is forward biased if the drop across R is not known?


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